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- Path: sparky!uunet!zaphod.mps.ohio-state.edu!moe.ksu.ksu.edu!ux1.cso.uiuc.edu!roundup.crhc.uiuc.edu!focus!hougen
- From: hougen@focus.csl.uiuc.edu (Darrell Roy Hougen)
- Newsgroups: sci.math
- Subject: Re: proof wanted 2
- Date: 8 Jan 1993 21:04:46 GMT
- Organization: Center for Reliable and High-Performance Computing, University of Illinois at Urbana-Champaign
- Lines: 24
- Message-ID: <1ikq9eINNmue@roundup.crhc.uiuc.edu>
- References: <1993Jan8.195646.1694@cc.umontreal.ca>
- NNTP-Posting-Host: focus.csl.uiuc.edu
-
- cazelaig@ERE.UMontreal.CA (Cazelais Gilles) writes:
-
-
- % n
- % Is it true that if C is a nonempty closed subset of R and x is a point
- % not in C that there exists a point c in C that is closest in C to x.
- %
- % i.e. such that: |x-c'| % = |x-c| for all c' in C.
-
- I'm a little rusty on analysis, but ..., intuitively, the closest
- point to x in C must be on the boundary of C which is no problem if C
- is closed.
-
- More precisely, if there were no closest point to x in C, that would
- imply that given any point c in C, one could find a point c'' in C
- that was closer to x. Therefore, one could construct a sequence of
- points in C such that each point was closer to x than its predecessor
- but whose limit point was not in C. But, if C is closed, then it
- contains all of its limit points, so there exists c' as defined above.
-
- Note that c' need not be unique. For c' to be unique, you need
- convexity of C.
-
- Darrell R. Hougen
-