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- From: mccoy@ils.nwu.edu (Jim Mccoy)
- Subject: Re: Simple problems to solve genetically
- Message-ID: <1993Jan10.054202.9817@ils.nwu.edu>
- Sender: usenet@ils.nwu.edu (Mr. usenet)
- Nntp-Posting-Host: aristotle.ils.nwu.edu
- Organization: The Institute for the Learning Sciences
- References: <1993Jan8.202702.21180@fcom.cc.utah.edu> <LAINS.93Jan8190731@world.std.com> <1993Jan9.192644.24693@fcom.cc.utah.edu>
- Date: Sun, 10 Jan 1993 05:42:02 GMT
- Lines: 54
-
- In article <1993Jan9.192644.24693@fcom.cc.utah.edu> freier@mail.physics.utah.edu (rodney james freier) writes:
- >In article <LAINS.93Jan8190731@world.std.com>, lains@world.std.com (Layne L Ainsworth) writes:
- >|>
- >|> On the BlackJack problem:
- >|>
- >|> aIt might be knd of interesting to give as input the history of all
- >|> cards turned up in the game (current shoe). Emergent card counting!
- >
- > Yes, that should give a better playing strategy, but at a huge cost.
- >To make a hit/stay decision, you need to know the value of your hand and
- >some reasonable number of the cards that have appeared up to this point.
- >This should always include the dealer's upcard and your two cards.
-
- It might be possible to allow some card counting without the huge costs you
- assume. For starters, one can make significant modification of the house
- percentage just by counting aces, face cards, and 10s. Additionally, one
- advantage that blackjack has over card games such as poker is that the card
- suit has no value. A jack of diamonds is equivalent in all cases to a jack
- of spades. This means that you only need to keep track of 13 categories
- with a value from 0-4, hence only 39 bits and not the 52 you mentioned.
- You could even decrease this number by storing all cards with a value of 10
- as a single number (now we are down to 32 bits, and only 8 bits to count
- aces and cards with a value of 10.)
- >
- > Let me compare that with the string size for the original problem.
- >
- > Item Number of possibilities
- > Hand's value 9
- > dealers upcard 52
- > Is hand splitable? 2
- >
- > This gives only 9*2*52 = 936 bits per string, or 117 bytes. That would
-
- Or we could try this:
-
- cards in hand: 10 bits, 5 per card (values 0-16, suit is irrellevant)
- dealers upcard: 5 bits
-
- By ignoring suit you will be able to cut out a major amount of noise from
- the strings you proposed. We could even add the 32 bits necessary to count
- a full deck as mentioned previously and still be way under the 936 bits you
- suggest. Then again, I could be missing something very obvious here...it
- has been a long day... :)
-
- jim
-
-
-
-
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