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- From: andy@ie.utoronto.ca (Andy Sun)
- Subject: why does an 6000 ft exabyte tape give 2.3Gb capacity?
- Message-ID: <C06Bpu.2IJ@ie.utoronto.ca>
- Organization: University of Toronto, Department of Industrial Engineering
- Date: Fri, 1 Jan 1993 11:53:54 GMT
- Lines: 24
-
- Hi Everyone,
-
- I know I am missing something, but I don't know what it is and will
- appreciate your help.
-
- I know for a fact (from the dump(8) man page) that a 2.3Gbyte 8mm
- Exabyte tape has a length of 6,000 feet and a density of 54,000 bits/inch.
- What I don't understand is WHY 6,000 feet with 54,000 bits/inch would give
- 2.3Gbyte?
-
- 54000 bits x 12 inch x 1 byte x 1 kbyte x 1 Mbyte x 1 Gbyte x 6000 feet
- ---- ------- ------ ---------- ----------- ----------
- inch 1 foot 8 bits 1024 bytes 1024 kbytes 1024 Mbyte
-
- = 0.45Gbyte
-
- Where does the extra factor of 5 come from?
-
- Andy
- --
- Andy Sun (andy@ie.utoronto.ca) 4 Taddle Creek Road, Toronto
- Computing Coordinator Ontario, Canada. M5S 1A4
- Department of Industrial Engineering Phone: (416) 978-8830
- University of Toronto Fax: (416) 978-3453
-