home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: alt.guitar
- Path: sparky!uunet!paladin.american.edu!europa.asd.contel.com!howland.reston.ans.net!zaphod.mps.ohio-state.edu!pacific.mps.ohio-state.edu!linac!att!cbnewsc!cbfsb!cbnewsg.cb.att.com!kew
- From: kew@cbnewsg.cb.att.com (steve.w.askew)
- Subject: Re: Tube swapping/amp question
- Message-ID: <1992Dec21.214958.6884@cbfsb.cb.att.com>
- Summary: Tube swappin
- Sender: news@cbfsb.cb.att.com
- Organization: AT&T
- References: <BzGywo.yE@acsu.buffalo.edu> <TOM.92Dec21114809@bailey.cpac.washington.edu>
- Distribution: usa
- Date: Mon, 21 Dec 1992 21:49:58 GMT
- Lines: 26
-
- In article <TOM.92Dec21114809@bailey.cpac.washington.edu>, tom@cpac.washington.edu (Tom May) writes:
- > In article <1992Dec21.162618.24450@cbfsb.cb.att.com> kew@cbnewsg.cb.att.com (steve.w.askew) writes:
- >
- > In the Carvin Im not sure, but in Marshall and Fender amps you could
- > always remove the 2 outside power tubes to reduce the power by 50%.
- > But you had better change the Impedence selector to compensate.
- >
- > So, I'm running with four tubes into a 16-ohm load, with the impedance
- > selector set to 16 ohms. If the plate current of each tube is I and
- > the 16-ohm speaker load as seen through the output transformer is R,
- > the voltage dropped across the transformer primary is 2IR (since there
- > are two tubes in parallel providing a total current of 2I). If I remove
- > the outside tubes without changing the impedance selector, the voltage
- > across the primary would be just IR, which is probably a bad thing.
- > In order to maintain the V=2IR relationship beteen plate current and
- > voltage to keep the tubes happy, I have to twiddle the impedance
- > selector to make R look twice as large (V=I*2R), which I can do by
- > setting the selector to 8 ohms. Right?
- > --
- > Tom, tube hacker in the making
-
- Uh Right!
- I will have to check my notes8^)
-
- Steve
- Doin That Blues ThAng!
-