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- Newsgroups: alt.folklore.science
- Path: sparky!uunet!spool.mu.edu!darwin.sura.net!sgiblab!sgigate!sgi!wdl1!wdl39!mab
- From: mab@wdl39.wdl.loral.com (Mark A Biggar)
- Subject: Re: More Monty Hall
- Message-ID: <1992Dec23.212954.4781@wdl.loral.com>
- Sender: news@wdl.loral.com
- Organization: Loral Western Development Labs
- References: <1h4fbgINN5c5@nz12.rz.uni-karlsruhe.de> <1992Dec21.214559.22343@berlioz.nsc.com> <1992Dec22.174608.24889@panix.com>
- Distribution: usa
- Date: Wed, 23 Dec 1992 21:29:54 GMT
- Lines: 19
-
- Lets formulate the problem slightly differently. Your are show two doors, D1
- and D2. One of which contains a prize and the other a goat. 50-50 right.
- Ah, but now I tell you that it is twice as likely that the prize is behind D1
- than it is behind D2. Do you still insist that because there are two doors it
- still a 50-05 pick? The extra rig-am-roll that Monty goes through (letting
- you pick one of three dorrs, then showing you that one of the other 2 doors
- has a goat) gives you exactly the same new information that the extra
- statement above gives you (i.e that it is twice as as likely that the
- prize is behind the door you didn't pick).
-
- Another way to look at it is like so: you decide to never switch and always
- stay with the door you picked first. As you have only a 1/3 chance of picking
- right door, you can win only 1/3 of the time. but that means that the
- alternitive (switching) must win 2/3 of the time.
-
- --
- Mark Biggar
- mab@wdl1.wdl.loral.com
-
-