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- From: roberts@cmr.ncsl.nist.gov (John Roberts)
- Newsgroups: sci.space
- Subject: Re: Micro-g in KC-135
- Message-ID: <BzKLqy.Aou.1@cs.cmu.edu>
- Date: 20 Dec 92 18:22:04 GMT
- Sender: news+@cs.cmu.edu
- Distribution: sci
- Organization: National Institute of Standards and Technology formerly National Bureau of Standards
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-
- -From: stick@lopez.marquette.MI.US (Stick,CommoSigop)
- -Subject: Re: Micro-g in KC-135
- -Date: 15 Dec 92 22:19:31 GMT
- -Organization: Great White North/UPLink
-
- -In <Bz7v1M.6DC@zoo.toronto.edu> henry@zoo.toronto.edu (Henry Spencer) writes:
-
- ->In article <1gfti1INNaqj@rave.larc.nasa.gov> claudio@nmsb.larc.nasa.gov (Claudio Egalon) writes:
- ->>What causes the microgravity in the KC-135, the centripetal
- ->>acceleration at the top of the parabola, which may cancel the gravity
- ->>acceleration, or something else???
-
- ->You don't "cancel" the gravitational acceleration, you fall with it. The
- ->KC-135 flies the exact trajectory that it would follow if it were falling
- ->free in a vacuum.
-
- ->That trajectory isn't exactly a parabola; it is in fact a segment of an
- ->elliptical orbit (one that intersects the Earth's surface). It's very
- ->close to being a parabola. It would *be* a parabola if the Earth were
- ->flat and gravity did not diminish with altitude.
-
- - Interesting. The way I see it, the -135, after nosing up, pushes over
- -in such a manner that its acceleration towards the Earth's surface exactly
- -matches the acceleration of gravity. And, I don't know for sure if its
- -flight path would be that of a parabola, it doesn't maintain its lateral
- -velocity vector. The speed vector parallel to the Earth's surface would be
- -at its greatest when the aircraft was in level flight.
-
- The horizontal velocity vector *has* to remain essentially the same, or
- you won't get zero-G.
-
- While the trajectory might technically be an ellipse, I think it's more
- practical to use the approximation that the Earth is flat, the gravitational
- field is constant, and the trajectory is a parabola. After all, over the
- course of a 30-second zero-G trajectory, the local intensity of the Earth's
- gravitational field should show an altitude-related variation of only about
- one part in 3000, and the Earth beneath the airplane should curve by only
- about 1/16 of a degree. The trajectory of the plane isn't precise enough
- to reflect such small differences.
-
- Approximations of this type are useful in many fields of engineering. For
- instance, among those who build their own amateur telescopes, a 4-inch f/10
- primary mirror used to be one of the popular choices, in part because for
- that size mirror, a spherical curvature (much easier to grind than a parabolic
- curvature) is sufficiently close to a parabola that further figuring isn't
- really needed.
-
- John Roberts
- roberts@cmr.ncsl.nist.gov
-