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- From: israel@unixg.ubc.ca (Robert B. Israel)
- Newsgroups: sci.math
- Subject: Re: Tiling problem
- Date: 20 Dec 92 09:26:50 GMT
- Organization: The University of British Columbia
- Lines: 64
- Message-ID: <israel.724843610@unixg.ubc.ca>
- References: <israel.723716857@unixg.ubc.ca> <israel.723837962@unixg.ubc.ca> <1gggutINN29q@access.usask.ca> <1gm373INNafn@access.usask.ca> <1992Dec18.002343.3944@infodev.cam.ac.uk> <1992Dec18.111210.2852@odin.diku.dk> <1992Dec20.000625.28213@infodev.cam.ac.uk>
- NNTP-Posting-Host: unixg.ubc.ca
-
- In <1992Dec20.000625.28213@infodev.cam.ac.uk> cet1@cus.cam.ac.uk (C.E. Thompson) writes:
-
- >But I then noticed, to my considerable astonishment, that Robert Israel's
- >later N = 13 solution:
-
- > 0001101010110
- > 0101011000011
- > 1100001101110
- > 0110101011000
- > 0101100001101
- > 0000110101011
- > 1011101100001
- > 0110000110111
- > 0011010101100
- > 1010110000110
- > 1000011011101
- > 1101110110000
- > 1011000011010
-
- >*does* satisfy the stronger condition, having no i x (13-i) rectangles with
- >four corners the same. Unless this is a consequence of his search strategy,
- >there is something very odd going on.
-
- As a matter of fact, there *is* something odd going on. A close look at
- this solution shows that all the rows are cyclic permutations of
- 001101a101100, where "a" is either 0 or 1, each row being displaced 5
- places to the left from the previous one. If you write one of these
- 13-tuples as <c_i>_{i=0..12}, it satisfies the condition that for all
- i and 1 <= j <= 12, c_i, c_{i+j}, c_{i+5j} and c_{i+6j} are not all the
- same (considering the subscripts mod 13). Thus such a 13-tuple generates
- a square that works (with periodic boundary condition). The only 13-tuples
- for which this works are these two and those obtained from them by cyclic
- permutation and interchanging 1 and 0. I also tried shifts other than 5
- (so for some b, 1<=b<=12, you want c_i,c_{i+j},c_{i+bj} and c_{i+(b+1)j}
- never to be all the same). No more examples except for b=8 (which is
- equivalent to b=5 by left<->right symmetry). Unfortunately, there are no
- 14-, 15-, 16- or 17-tuples with the analogous properties either.
-
- I don't think that my search strategy has any inherent bias towards
- solutions with any particular regularity or periodicity. I tried running
- the 13 x 13 square again, with the following result:
-
- 1011010011010
- 0001111010110
- 0111001000011
- 1100011101010
- 1001010100111
- 0101110001101
- 0000100111011
- 1010111100001
- 0110010110101
- 0011001101100
- 1110101000110
- 1000001011101
- 1101100110000
-
- If there's structure here, it's certainly more subtle than last time.
- I haven't checked whether this satisfies the periodic boundary condition.
-
- --
- Robert Israel israel@math.ubc.ca
- Department of Mathematics or israel@unixg.ubc.ca
- University of British Columbia
- Vancouver, BC, Canada V6T 1Y4
-