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- Path: sparky!uunet!pipex!warwick!uknet!rook.ukc.ac.uk!eagle.ukc.ac.uk!wabe
- From: wabe@ukc.ac.uk (W.A.B.Evans)
- Newsgroups: sci.math
- Subject: Re: Orbital motion question
- Message-ID: <2603@eagle.ukc.ac.uk>
- Date: 14 Dec 92 19:15:34 GMT
- References: <1ggfesINN29q@access.usask.ca>
- Reply-To: wabe@ukc.ac.uk (W.A.B.Evans)
- Organization: Computing Lab, University of Kent at Canterbury, UK.
- Lines: 40
- Nntp-Posting-Host: eagle.ukc.ac.uk
-
- In article <1ggfesINN29q@access.usask.ca> choy@skorpio.usask.ca (I am a terminator.) writes:
- >
- >Let the vector r be the position of a mass m orbiting in a plane around
- >another mass M (which doesn't move) at the origin. The mass m is
- >accelerated such that
- >
- > 2
- > d r KMm
- >m --- = - ---- r
- > 2 2
- > dt |r|
- >
- Do you REALLY mean an inverse FIRST Power Law or the usual inverse
- SQUARE Law - in the which case you should have
-
- 2
- d r KMm
- m --- = - ---- r
- 2 3
- dt |r|
-
- > r
- > d---
- > |r|
- >What is the scalar product of r/|r| and ------ ?
- > dt
- >
- The rate of change with time of the unit radial vector is
-
- d theta
- ------- x unit vector theta ( in polar co-rds r,theta)
- dt
-
- and, so is always perpendicular to the unit radial vector. This is true
- whatever the central force - or whether your orbit is elliptic, parabolic
- or hyperbolic ( inverse SQUARE force). It would also be true for other orbits
- which in general would not be closed i.e. they precess.
-
- W. Alan B. Evans
- [ wabe@ukc.ac.uk ]
-