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- Xref: sparky sci.crypt:5726 alt.security.pgp:200
- Path: sparky!uunet!usc!sdd.hp.com!ncr-sd!crash!nadir!crespin
- From: crespin@nadir.uucp (Rudy Crespin)
- Newsgroups: sci.crypt,alt.security.pgp
- Subject: RSA Question (was Re: PKP/RSA comments on PGP legality)
- Message-ID: <dOsLrAnGBh107h@nadir.uucp>
- Date: Tue, 15 Dec 92 21:50:21 -0800
- References: <1992Dec14.190615.13954@macc.wisc.edu>
- Organization: UUCP San Diego, CA
- Lines: 23
-
- In <1992Dec14.190615.13954@macc.wisc.edu> stevens@vms.macc.wisc.edu (PAul STevens - MACC - 2-9618) writes:
- > For the record I am going to publish a number I
- > want to keep secret. I am going to raise it to the power of
- > three modulo 91 which is the product of two primes. The
- > result is 34. My wife knows the factors of 91 and will be able
- > to decode this message.
-
- Please excuse my ignorance, but, how can "your wife" decode the message
- knowing 34, 91, 7, and 13?
-
- i.e. I have a number
- (X^3) moulo 77 (product of two primes) = 48
- what is my number? and how did you get the answer?
-
- Thanks,
- Rudy Crespin
-
- --
- _ _
- --- O | Rudy Crespin | / \ |\ | __ / \ |\ |
- -- <^- | crespin@nadir.uucp | \_/ | \| \_/ | \|
- -- -\/\ | crash!nadir!crespin |
- --- \ | |- No-No, it is On-On.
-