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- Newsgroups: rec.puzzles
- Path: sparky!uunet!usc!rpi!batcomputer!cornell!karr
- From: karr@cs.cornell.edu (David Karr)
- Subject: Re: Trig. inequality
- Message-ID: <1992Nov22.050428.28191@cs.cornell.edu>
- Organization: Cornell Univ. CS Dept, Ithaca NY 14853
- References: <1ekddfINNi96@uwm.edu> <1992Nov22.030801.4773@dartvax.dartmouth.edu>
- Date: Sun, 22 Nov 1992 05:04:28 GMT
- Lines: 20
-
- In article <1992Nov22.030801.4773@dartvax.dartmouth.edu> J.Theodore.Schuerzinger@dartmouth.edu (J. Theodore Schuerzinger) writes:
- >In article <1ekddfINNi96@uwm.edu>
- >radcliff@csd4.csd.uwm.edu (David G Radcliffe) writes:
- >
- >> Show that (sin x)^(sin x) < (cos x)^(cos x) when 0 < x < pi/4.
- >
- >[...] (cos x)^2 will be greater than (sin x)^2 from 0<x<pi/4. I
- >haven't taken any math since freshman year of college, [...]
-
- We could have figured the last part out ourselves. :-)
-
- The problem is you DON'T have (sin x)^2 on the left, you have
- (sin x)^(sin x), which is considerably bigger. The behavior of
- this object as x->0 is not as obvious as that of any fixed power
- of sin(x).
-
- -- David Karr (karr@cs.cornell.edu)
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