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- From: adrian@stein.u.washington.edu (Adrian Mariano)
- Subject: Re: winning ratio
- Message-ID: <1992Nov18.060917.27210@u.washington.edu>
- Sender: news@u.washington.edu (USENET News System)
- Organization: University of Washington
- References: <Bxq5pn.D89@nic.umass.edu> <1992Nov15.142906.30095@dickens.com> <1992Nov17.023826.2810@bhprtc.scpd.oz.au> <1992Nov18.021006.14737@uxmail.ust.hk>
- Date: Wed, 18 Nov 1992 06:09:17 GMT
- Lines: 36
-
- In <1992Nov18.021006.14737@uxmail.ust.hk> schmidt@uxmail.ust.hk (DR. ROY SCHMIDT) writes:
-
- >>>
- >>>P = 1/2 * (2/3)^(2*d)
- >>>
- >>>where d is the absolute rank difference and P is the probability
- >>>that the weaker player will win.
-
- >There are several problems with such a "formula" approach.
-
- >1. If we assume no difference in ranks, then the formula yields a
- > probability of 0.333 of a given player winning. Since the game is
- > not three-handed, we would have to assign the remaining 1/3 to draws
- > Having played not a few games in my life, draws just don't seem to
- > come up often enough :-).
-
- No. 1/2 * (2/3)^0 = 1/2. This is the expected result.
-
- >2. Such a formula would have to be strength-dependent. That is, the
- > probability that a 16-kyu would beat a 12-kyu is likely much higher
- > than the probability that a ten-kyu would beat a six-kyu in an even
- > game, and so forth.
-
- So you would think, but it turns out not to be the case.
-
- [ one problem omitted]
-
- >4. The formula lacks an empirical basis. First, you have to find a
-
- The formula was obtained from study of over 2000 games played in
- tournaments. The study was done by Jos Vermaseren. This doesn't
- conform to the (omitted) guidlines you demand, but it is the best
- emperical basis you can reasonably expect. It shows (to some degree)
- what happens when real people with real ranks (however they were
- determined) play games.
-
-