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- From: cb919@cleveland.Freenet.Edu (Mike Bolduan)
- Newsgroups: k12.ed.math
- Subject: Re: A Nice Geometry Problem
- Date: 20 Nov 1992 21:09:54 GMT
- Organization: Case Western Reserve University, Cleveland, Ohio (USA)
- Lines: 26
- Message-ID: <1ejk72INNn92@usenet.INS.CWRU.Edu>
- NNTP-Posting-Host: hela.ins.cwru.edu
-
-
- The circle asked for is of course known as the in-circle of the
- triangle. I won't spoil people's fun in solving it, but the answer is
- one of those cases where you will say "gee that's neat -- I didn't
- know that!"
- As an extension: draw the 3-4-5 triangle and label as ABC (B at the 90
- degree angle). Extend all three sides. Now find the radii of the
- three circles, each of which is tangent to one of the sides (extrnally)
- and the other two sides extended. For instance, one such circle
- is tangent to BC and to AC extended and to AB extended. Again,
- the results are not well-known and are "interesting".
-
- On a related note: Students learn in high school trig about the
- law of Sines (at least I HOPE they still do!!! :-) ) which says
- that the ratio a/sin A = b?sin B = c/sin C. That is, this
- particular ratio is a constant. The question for you out there in
- math=-land is: what is the significance of this particular
- constant? i.e., what does it have to do with the original
- triangle. Another gee whiz type answer.
- enjoy
- mike
- bolduan @catlin onn bitnet
- bolduan@catseq.catlin.edu on internet
- --
- mike bolduan
- bolduan@catlin
-