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- From: blalock@hpl-opus.hpl.hp.com (Travis Blalock)
- Date: Wed, 18 Nov 1992 18:33:45 GMT
- Subject: Re: Re: Lifetime of 25MHz IIsi (was: 25MHz IIsi and my engineering friend)
- Message-ID: <71610003@hpl-opus.hpl.hp.com>
- Organization: HP Labs, High Speed Electronics Dept., Palo Alto, CA
- Path: sparky!uunet!charon.amdahl.com!pacbell.com!sgiblab!sdd.hp.com!hpscit.sc.hp.com!scd.hp.com!hpscdm!hplextra!hpl-opus!blalock
- Newsgroups: comp.sys.mac.hardware
- References: <1992Nov16.181708.22881@news.uni-stuttgart.de>
- Lines: 24
-
- In comp.sys.mac.hardware, blalock@hpl-otis.hpl.hp.com (Travis Blalock) writes:
-
- > In comp.sys.mac.hardware, isr@rodan.acs.syr.edu (Michael S. Schechter - ISR group account) writes:
- >
- > > they'll be more voltrage drop, and the CPU will draw still more amperage,
- >
- > Ack! Less voltage --> lower current
- >
- Clarification: Some folks don't understand why I am referring to this
- situation as less voltage. The power supply voltage is fixed. More voltage
- drop on the PC board trace between the supply and the CPU chip means there is
- less voltage across the CPU chip. If the CPU has less voltage across
- it, it will draw less current.
-
- V(CPU) = V(supply) - V(PC board trace voltage drop)
-
- I know this is probably obvious to most readers but some mail I got seemed to
- imply that the CPU voltage would remain fixed and the power supply output
- voltage would increase as the PC board trace resistance increased. This is
- not how the system is configured. The power supply voltage is fixed.
-
- Travis Blalock
- blalock@hpl.hp.com
-
-