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- From: watson@maths.uwa.oz.au (David Watson)
- Newsgroups: comp.graphics
- Subject: Re: Point inside a triangle
- Message-ID: <1eeln8INN79e@uniwa.uwa.edu.au>
- Date: 19 Nov 92 00:04:56 GMT
- References: <1992Nov16.115211.23169@sophia.smith.edu> <1e9c3cINN4hi@uniwa.uwa.edu.au> <1e9k0cINNc0q@uniwa.uwa.edu.au> <1992Nov17.033031.1896@sophia.smith.edu>
- Organization: The University of Western Australia
- Lines: 16
- NNTP-Posting-Host: madvax.maths.uwa.oz.au
-
- orourke@sophia.smith.edu (Joseph O'Rourke) writes:
-
- >In article <1e9k0cINNc0q@uniwa.uwa.edu.au> watson@maths.uwa.oz.au (David Watson) writes:
-
- >>and if b0 == 0 => (x1 == x2 && x1 == x3 && y1 == y2 && y1 == y3)
-
- >I think you meant to say if b0 == 0, then the three triangle vertices
- >are collinear: the above implication is too strong.
-
- Yes, of course, when the three points are colinear the area is zero
- also.
- --
- Dave Watson Internet: watson@maths.uwa.edu.au
- Department of Mathematics
- The University of Western Australia Tel: (61 9) 380 3359
- Nedlands, WA 6009 Australia. FAX: (61 9) 380 1028
-