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- From: poonen@digel.Berkeley.EDU (Bjorn Poonen)
- Subject: paths and multisets
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- Sender: Daniel Grayson <dan@math.uiuc.edu>
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- Organization: U.C. Berkeley Math. Department.
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- Approved: Daniel Grayson <dan@math.uiuc.edu>
- Date: Thu, 30 Jul 1992 14:45:26 GMT
- Lines: 41
-
- QUESTION: Suppose you have an n-element multiset S deforming into another
- n-element multiset T. Can you find a path from a given element of S to some
- element of T?
-
- More precisely, let M be a topological space and give M^n the product topology.
- Let the symmetric group S_n act on M^n by permuting the coordinates, and give
- M^n/S_n the quotient topology. (M^n/S_n is the space of n-element multisets.)
- Suppose w : [0,1] -> M^n/S_n is a continous path, and P is an element of the
- multiset w(0). Can one find a path w_1 : [0,1] -> M such that w_1(0)=P and
- w_1(t) is an element of w(t) for all t in [0,1]?
-
- Assume that M has nice properties, if it helps. I need the case M=R^2 (i.e.,
- the plane). (The application is the following: take all polynomials
- 1 + e_1 z + e_2 z^2 + ... + e_n z^n
- where each e_i is 0 or 1, and n is arbitrary. Let W be the set of all complex
- zeros of such polynomials. I have proved that the closure of W is connected.
- If the question above has a positive answer, I can prove that it is path
- connected as well.)
-
- More generally one can ask whether the path w : [0,1] -> M^n/S_n can always be
- decomposed into n paths w_1,w_2,...,w_n in M. This is equivalent to asking
- whether the path can be lifted to a path in M^n. (This would certainly imply a
- positive answer to the first question.)
-
- Here is what I know so far. If M=R this general result is true. (Let w_k(t)
- be the k^th largest element of w(t).) If M=R^2 and n=2, the result is true.
- (The map M^n -> M^n/S_n is a covering projection if one deletes the places
- where two elements of the multiset coincide, so one can lift the path on each
- (open) connected component of the set of t for which w(t) has distinct
- elements. For n=2, this suffices, since for the remaining values of t, there
- is only one possible lift of w(t).)
-
- Please e-mail solutions, useful references, or comments to me at
-
- poonen@research.att.com before August 24
- poonen@math.berkeley.edu after August 24
-
- Bjorn Poonen
-
-
-
-