home *** CD-ROM | disk | FTP | other *** search
- Path: sparky!uunet!wupost!waikato.ac.nz!comp.vuw.ac.nz!cc-server4.massey.ac.nz!TMoore@massey.ac.nz
- Newsgroups: sci.math
- Subject: Re: HELP. TEST FOR EXTREMA IN f(x,y,z)
- Message-ID: <1992Jul30.221230.21146@massey.ac.nz>
- From: news@massey.ac.nz (USENET News System)
- Date: Thu, 30 Jul 92 22:12:30 GMT
- References: <1992Jul29.010542.8650@eng.ufl.edu>,<a_rubin.712451081@dn66> <1992Jul30.144053.28402@news.cs.brandeis.edu>
- Organization: Massey University
- Lines: 27
-
- In article <1992Jul30.144053.28402@news.cs.brandeis.edu>, palais@binah.cc.brandeis.edu writes:
- >
- > Armando Barre asked
- >
- > >My question is :
- >
- > >IS THERE SUCH A TEST FOR EXTREMA IN A FUNCTION OF 3 VARIABLES :f(x,y,z) ?
- >
- > Actually there is; someone else will have to provide a reference, but:
- >
- > (i) f(a,b) is a local maximum if the Hessian is negative definite
- > (ii) f(a,b) is a local minimum if the Hessian is positive definite
- > (iii) f(a,b) is a local minimum if the Hessian is indefinite.
- >
- > Arthur Rubin answered:
- >
- > I think Arthur meant to say saddle point for case (iii) (but one must
- > assume that the Hessian matrix is non-singular). The same result is true
- > in any dimension (and even in Hilbert space). The best reference is to any
- > proof of the "Morse-Lemma", which says that after a change of variables the
- > function locally is equal to a constant (its value at the critical point)
- > plus the quadratic function given bythe Hessian. (See Lang's "Differentiable
- > Manifolds" for the Hilbert space proof.)
- >
- Of course there is a fourth case. When the Hessian is zero the stationary
- point might be any of those types. This also applies in case (iii) if the
- Hessian does not have full rank.
-