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- Newsgroups: sci.math
- Path: sparky!uunet!mcsun!sunic!ugle.unit.no!levangerhs.no!ap
- From: ap@levangerhs.no (Andrei Prasolov)
- Subject: Re: ALGEBRAIC NUMBER ARITHMETIC
- Message-ID: <1992Jul29.163830.6443@ugle.unit.no>
- Keywords: Algebraic numbers, Arithmetic operations
- Sender: news@ugle.unit.no (NetNews Administrator)
- Organization: Hogskolen i Levanger
- Date: Wed, 29 Jul 92 16:38:30 GMT
- Lines: 28
-
- This is the answer to article 22109.
-
- Operating with algebraic numbers one does not need
- to know the interval. For arithmetical operations
- it does not matter WHICH root of the (irreducible!)
- equation is taken. It does matter ONLY if you wants
- to calculate the root (approximately, of course).
- First prove a very simple theorem:
- TH. A complex number x is algebraic iff there exists
- a fin-dim Q-subspace V of C s.t. xV lies in V.
- PF. => V is generated by 1, x, x^2, ..., x^(n-1) where n is
- the degree of the polynomial.
- <= x is a root of the characteristic polynomial of the
- multiplication by x : V -> V.
-
- Now if V serves for x, and W serves for y, then
- VW serves for xy, x+y, x-y. For 1/x just take the mirror reflexion
- of a polynomial.
-
- Andrei PRASOLOV
- Hoegskolen i Levanger
- Kirkegt 1, 7600 Levanger
- Norway
-
- Tel. 47-76-89157 (office), 47-76-89688+2304 (home)
- Telefax 47-76-89155, e-mail AP@LEVANGERHS.NO
-
-
-