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- Newsgroups: sci.math
- Path: sparky!uunet!usc!sdd.hp.com!mips!news.cs.indiana.edu!noose.ecn.purdue.edu!gn.ecn.purdue.edu!prasanth
- From: prasanth@gn.ecn.purdue.edu (Ravi K. Prasanth)
- Subject: Re: An interesting limit problem.
- Message-ID: <1992Jul26.131637.863@gn.ecn.purdue.edu>
- Organization: Purdue University Engineering Computer Network
- References: <1992Jul25.212844.1@lure.latrobe.edu.au>
- Date: Sun, 26 Jul 92 13:16:37 GMT
- Lines: 36
-
- In article <1992Jul25.212844.1@lure.latrobe.edu.au>, mattm@lure.latrobe.edu.au writes:
- > A challenge to all mathematicians. A 100 years ago, this would probably have
- > been solved fairly simply in a natural way, but can you? I think that this
- > problem was first posed by the Russian mathematician Arnold. Hope you find this
- > problem as interesting as I did when I first solved it.
- >
- > sin(tan x) - tan(sin x)
- > lim ---------------------------------- = ???
- > x->0 arcsin(arctan x) - arctan(arcsin x)
- >
- > Tim email: mattm@lure.latrobe.edu.au
-
- Suppose y = arcsin(arctan(x)). Then x = tan(sin(y)). Note that
- y(x) is continuous at x = 0 and x(y) is conitnuous at x. Also,
- if x -> 0 from above (below), then so does y -> 0.
-
- Substituting for x in the expression whose limit is to be
- found we get
-
- arcsin(arctan y) - arctan(arcsin y)
- ----------------------------------
- sin(tan y) - tan(sin y)
-
- But this is exactly the inverse of the expression whose limit
- is to be found. Therefore, the limit exists and is equal to 1.
-
- sin(tan x) - tan(sin x)
- lim ---------------------------------- =
- x->0 arcsin(arctan x) - arctan(arcsin x)
-
- arcsin(arctan x) - arctan(arcsin x)
- lim ---------------------------------- = 1
- x->0 sin(tan x) - tan(sin x)
-
- Ravi K. Prasanth
-
-