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- Newsgroups: sci.math
- Path: sparky!uunet!stanford.edu!leland.Stanford.EDU!algebra
- From: algebra@leland.Stanford.EDU (Leong Weng Ng)
- Subject: Re: A puzzle!
- Message-ID: <1992Jul25.003619.23447@leland.Stanford.EDU>
- Keywords: Math, puzzle
- Sender: news@leland.Stanford.EDU (Mr News)
- Organization: DSG, Stanford University, CA 94305, USA
- References: <chepan.712011867@gsusgi1.gsu.edu>
- Date: Sat, 25 Jul 92 00:36:19 GMT
- Lines: 23
-
- In article <chepan.712011867@gsusgi1.gsu.edu> chepan@gsusgi1.gsu.edu (Parthasarathy Nambi) writes:
- >
- >
- > Here is something for puzzle lovers:
- >
- > Below is a sequence of numbers, can you find the next two numbers and
- > the general formula for generating numbers in this sequence:
- >
- > The numbers are:
- >
- > 4, 72, 21600, 190512000, 58090919040000, etc
-
- nth term = (P)^(P) * (P)^(P) * ... * (P)^(P)
- 1 n 2 n-1 n 1
- where P is the nth prime.
- n
-
- > If you know the answer please post a response in this group.
- >
- >
- > P.Nambi
-
-
-