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- ;demo03-03.bb - Counts using step amounts
- ;loop backwards, from 5.0 to 0.0 by -1.2
- For counter# = 5.0 To 0.0 Step -1.2
- ;print out 3 digits of counter, so 5.000000 becomes 5.0 - decimal is a digit
- Print Left$( Str counter, 3)
- Next
-
- ;Delay for five seconds
- Delay 5000