ocr: Oxidation Reduction 2H20+502-S04 (add H20 to balance 0 6-31 balance the number of I atoms in products) present) 2H20+ +S02-504+4H (add H+ to 26+1-3 (add to balance side with balance Hin reactants) higher charge) 2H20 + S02-S04 +4H'+26(add to balance side with higher charge)
