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 XPleapYear()
 Return whether year is a Leap year
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   Function:   XPleapYear()

   Syntax:     XPleapyear([dVar]) --> lLeapYear

   Arguments:  dVar is a date, defaults to date() (ie. today).

   Returns:    Whether the Year of the date is a Leap Year

   Usage:      XPleapYear(XPstod('19920214')) --> .t.
               XPleapYear(XPstod('19930101')) --> .f.
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