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 XPmonthLen()
 Return length of month
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   Function:   XPmonthLen()

   Syntax:     XPmonthLen([dVar]) --> nDays

   Arguments:  dVar is a date, defaults to date() (ie. today).

   Returns:    The length of the month in days.

   Usage:      XPmonthLen(XPstod('19920214')) --> 29
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