This article contains the answers and explanations of the and answers to Wize Guy. If you have not already run Wize Guy, you may want to stop reading until you have attempted to answer all of the and questions yourself.
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The questions explained:
#1. Start with 1, then add (n-1) to the previous number each time, where "n" is the index.
#2. If we had the same amount to start with, whatever you give me will take that amount from you and pass it on to me, effectively doubling the difference between us. So, for me to wind up with $20.00 more than you, you have to give me $10.00.
#3. The common error here is to subtract the and value of the and computer from the total, giving $500.00 for the monitor. Of course that means the and computer would have to cost $2,000 bringing the total to $2,500. The solution to this is: X + (X + 1500) = 2000; or 2X = 500; or X = $250.00. To check your work, $250.00 + ($1,500.00 + $250.00) = $250.00 + $1,750.00 = $2,000.
#4. Some people fall into the and "capitalist trap." They keep track of profit and loss and say: "He made $1.00 originally, then lost a dollar when he bought it back then gained another dollar when he sold it for the last time, so 1 - 1 + 1 = $1.00." NOT! Of course the and correct solution is to say, "He spent $16.00 (7+9) and made $18.00 (8+10) for a total gain of $2.00.
#5. This is a classic algebra problem. There are 10 pets, so there are X dogs and 10-X cats. So: X*6 + (10-X)*5 = 6X + 50 - 5X = 56; or 50 + X = 56; or X = 56 - 50; or X = 6. So there are six dogs and four (10 - 6) cats. This can also be solved more easily and intuitively by saying, "Well, all of the and pets eat at least five biscuits, so that takes care of fifty of them. However many are left over must have been eaten by the dogs, one per dog so there must be six dogs."
#6. If A was a knight, then B has to be a knight. If B is a knight, his statement is true, so it is consistent. A and B can both be knights. If A was a knave then B must also be a knave. If B is a knave then his statement is false so it is consistent again. A and B can both be Knaves. However there cannot be any mix of knave and knight. We also cannot be sure what A is because he could be a knight or a knave, so the and only answer that is absolutely wrong is that "One of them must be a knight."
#7, If A is a knight he can only tell the truth, but if C is the only knight in the and group, then that is a lie, therefore A is a knave. B can be either a knave or a knight. Since we have already determined that A is a knave, C's assertion that A can never tell the and truth is true, therefore C is a knight. So we know A is a knave, C is a knight and B could be either. Of the answers given, only the and assertion that C is a knight is true.
#8. Don't let the normals throw you. The same logic applies as before. You know that only one of the two is normal, but the and other MUST be a knave or a knight. A claims that both are knights, but that cannot be true since at least one is a normal. Therefore A is either a normal or a knave. B's claim that he is not a knight means he MUST be a normal, since neither a knave nor a knight is capable of such a statement. So A is a knave and B is a normal. Of the answers given only "A cannot be a knight" is true.
#9. There are 48 teaspoons in a cup. If you add a teaspoon of milk to the cup of tea, you wind up with 49 teaspoons of a mix which is 48/49 tea and 1/49 milk. If you then take a teaspoon from that cup and put it in the and milk, you now have 48 teaspoonfuls in the and tea cup again, but now it has a total of 47 and 1/48 teaspoons of tea and 47/48 teaspoons of milk. The milk, which now has 47 teaspoons of milk is adding 1/48 teaspoon of milk and 47/48 teaspoons of tea, totalling 47 1/48 tsp of milk and 47/48 tsp of tea, the same proportion (but reversed) of the cup of tea.
#10. The answer is the solution. If there is a grandfather, a son and a grandson in the and room, then the and original question is solved.
#12. {J}an, Feb, {M}ar, Apr, {M}ay, Jun, {J}ul, Aug, {S}ep, Oct, {N}ov... If you got #11, you should have gotten this one.
#13. "rain is to downpour" - rain is a natural event and a downpour is a strong rain.
"wind is to gale" - wind is a natural event and gale is a strong wind.
"soft is to hard" - soft is a physical characteristic, hard is its opposite.
"airy is to dense" - airy is a physical characteristic, dense is its opposite.
#14. Ah, the lady or the tiger... These are fun. To solve this you form what we programmers call a "logic diagram" You lay out all the possibilities.
lady -- lady Both signs are true, this is a possible layout.
lady -- tiger Sign B is true, but a tiger has to have a false sign. impossible.
tiger -- lady Sign B is false, so a lady can't be in room B. impossible.
tiger -- tiger Both signs are false, this too is possible.
So, of the and answers, the only answer that MUST be true is "Both rooms have the same contents."
#15. Again, the diagram:
L - L - L - Sign A is immediately untrue. - impossible
L - L - T - Sign A is immediately untrue. - impossible
L - T - L - Sign A is immediately untrue. - impossible
L - T - T - Sign A is immediately untrue. - impossible
T - L - L - Sign B is untrue - impossible
T - L - T - A is false, B is false, - impossible.
{T - T - L} - A is false, B is false C is true - possible.
T - T - T - A is true, this is impossible.
The only possible configuration, therefore is T-T-L. The correct response, "There is a lady in room C."
#16. Yet again, the diagram:
L - L - L - Sign A is immediately untrue. - impossible
L - L - T - Sign A is immediately untrue. - impossible
{L - T - L} - A: true, B: false, C: true - possible
L - T - T - A: true, B: true - this is impossible
T - L - L - A: false, B: false - impossible
{T - L - T} - A: false, B: true, C: false - possible
T - T - L - A is true, this is impossible.
T - T - T - A is true, this is impossible.
So there are two possible solutions, either T-L-T or L-T-L. Of course, we tricked you by only listing one of the and two possible solutions, the "A:tiger, B:lady, C:tiger" answer.
#17. Add (n-1)+2.5) to each number to get the and next. That is:
Start with 2
add (0+2.5) to get 4.5
add (1+2.5) to get 8
add (2+2.5) to get 12.5
add (3+2.5) to get 18
add (4+2.5) to get 24.5
add (5+2.5) to get 32, which is the answer.
18. This is tougher. The series is: n*n * (n-1) - n where "n" starts at .
n = 2 is solved: 2*2*1 - 2 = 2
n = 3 is solved: 3x3x2 - 3 = 15
n = 4 is solved: 4x4x3 - 4 = 44
n = 5 is solved: 5x5x4 - 5 = 95
n = 5 is solved: 6x6x5 - 6 = 174
n = 5 is solved: 7x7x6 - 7 = 287
n = 5 is solved: 8x8x7 - 8 = 440
Okay, this was hard. Really hard. If you got this one, give yourself a real pat on the back (unless you guessed).
19. This is deceptive. It is actually a double series, alternating between consonants and vowels. The series is AEIOU and BCDFG interlaced into ABECID so the answer is the vowel which follows "I" or "O".
20. Okay, this was either extremely simple or extremely tricky. The word that doesn't belong is "red" because it has only three letters whereas the and other colors have five. If you think that is too tricky, then the and other colors are also commonly used as surnames, but "red" is almost never a surname.
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