ocr: CH111 QUIZ2 1988 PAGE3 3. (15 pts) 5. Combustion of diborane, 82"6 proceeds according to the equation 82"619) + 30,(9) * B20g(s) * 3H,0lg) and 1935 kJ are liberated per mole of - B,"6. : Combustion of boron metal B203 of kJ also per diborane, mole proceeds formed. of to 32*6. The water. the standard product (Suggestion: Calculate 8203, enthalpy the start and of with standard gives a formation out balanced enthalpy of 2356 kJ H20(g) of per Is thermochemical formation mole 241.0 of equation for each statement above.) 3 H20 + - B,03 1> 301 + BaH, + 1935 2B + %0, 1 B,03 -2356 3H, + %0, 1 - 3H20 3( ...
