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etime.m
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1998-11-10
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## Copyright (C) 1996, 1997 John W. Eaton
##
## This file is part of Octave.
##
## Octave is free software; you can redistribute it and/or modify it
## under the terms of the GNU General Public License as published by
## the Free Software Foundation; either version 2, or (at your option)
## any later version.
##
## Octave is distributed in the hope that it will be useful, but
## WITHOUT ANY WARRANTY; without even the implied warranty of
## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
## General Public License for more details.
##
## You should have received a copy of the GNU General Public License
## along with Octave; see the file COPYING. If not, write to the Free
## Software Foundation, 59 Temple Place - Suite 330, Boston, MA
## 02111-1307, USA.
## usage: etime (t1, t0)
##
## Return the difference between t1 and t0 in seconds. The arguments
## are expected to be vectors in the form returned by clock ().
##
## See also: tic, toc, clock, cputime
## Author: jwe
function secs = etime (t1, t0)
if (nargin != 2)
usage ("etime (t1, t0)");
endif
if (is_vector (t1) && length (t1) == 6 && is_vector (t0) && length (t0) == 6)
if (t1 (1) != t0 (1))
error ("etime: can't handle timings over year boundaries yet");
endif
## XXX FIXME XXX -- could check here to ensure that t1 and t0 really do
## make sense as vectors returned from clock().
days_in_months = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];
if (is_leap_year (t1 (1)))
days_in_months (2) = days_in_months (2) + 1;
endif
d1 = sum (days_in_months (1:(t1 (2) - 1))) + t1 (3);
d0 = sum (days_in_months (1:(t0 (2) - 1))) + t0 (3);
s1 = 86400 * d1 + 3600 * t1 (4) + 60 * t1 (5) + t1 (6);
s0 = 86400 * d0 + 3600 * t0 (4) + 60 * t0 (5) + t0 (6);
secs = s1 - s0;
else
error ("etime: args are not 6-element vectors");
endif
endfunction