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OCR: Memory Source 20000 2000 pointe 2000 Last 0003 20002 byte 20003 copied 20004 2000 20005 Destination 20006 0004 20007 H pointer 0003 Memor 20000 DS 2000 2000 20002 0006 Source 20003 Dostination block 20004 block 2000 20005 20006 0007 2000 0000 (c) The effect of this modification of the source blod the B that was just copied S copied again to the second element of the destination block. Given the original source block of A should have been copied to this position in the destination block In fact. copied by every repetition of rep movsh in this case D) Ultimately every byte of the destination block set DF must be as to1 for this sort of block copy, with the copy proxceeding from higher to lower addresses Refer to Figure 11.3 for an illustration of the proper operation Of this paricular block ...