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ltostr.c
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C/C++ Source or Header
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1994-04-03
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/*
** LTOSTR.C -- routine and example program to convert a long int to
** the specified numeric base, from 2 to 36.
**
** Written by Thad Smith III, Boulder, CO. USA 9/06/91
** and contributed to the Public Domain.
*/
#include <stdlib.h>
char * /* addr of terminating null */
ltostr (
char *str, /* output string */
long val, /* value to be converted */
unsigned base) /* conversion base */
{
ldiv_t r; /* result of val / base */
if (base > 36) /* no conversion if wrong base */
{
str = '\0';
return str;
}
if (val < 0) *str++ = '-';
r = ldiv (labs(val), base);
/* output digits of val/base first */
if (r.quot > 0) str = ltostr (str, r.quot, base);
/* output last digit */
*str++ = "0123456789abcdefghijklmnopqrstuvwxyz"[(int)r.rem];
*str = '\0';
return str;
}
#include <stdio.h>
main()
{
char buf[100], line[100], *tail;
long v;
int inbase, outbase;
for (;;)
{
printf ("inbase, value, outbase? ");
fgets (line, sizeof line, stdin);
sscanf (line, " %d%*[, ]%[^, ]%*[, ]%d", &inbase, buf, &outbase);
if (inbase == 0)
break; /* exit if first number 0 */
v = strtol (buf, &tail, inbase);
ltostr (buf, v, outbase);
printf ("=%ld (10) = %s (%d).\n", v, buf, outbase);
};
return 0;
}