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XPdoy()
Return day of Year
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Function: XPdoy()
Syntax: XPdoy([dVar]) --> nDoy
Arguments: dVar is a date, defaults to date() (ie. today).
Returns: The number of that Day in the Year. January 1st is day
#1, December 31st is the 365th of 366th day of the year.
Usage:
See Also:
XPweekNr()
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