CrackMe® Practices for Newbies
VBCrackMe 6 by Eternal Bliss

Simplest road for this one...
Saturday, 13-Mar-99 23:41:15

    I found the simplest solution to this problem, if you don't care what the user name is, is to enter @@@@@@@@ as the user name. When the ascii value is taken, converted to octal, and then the rightmost 2 digits taken, the result is 0. With @@@@@@@@ as the uid, the serial # is 0 regardless of the timers. Simple, indeed.

    Zzzap


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Simplest road for this one... (Zzzap) (13-Mar-99 23:41:15)

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