CrackMe® Practices for Newbies ~ Moderated

Re: Re: Re: Cracked dat file
Sunday, 31-Jan-99 20:01:29
    206.248.47.196 writes:

    Well I have cracked the .dat file with my name and this is how it looks.


    00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
    3C 1F 5A DB 3A AC 28 CF 3E 1F 24 00 00 00 00 00
    00 00 00 00 50 52 49 4E 43 45 53 53 00 00 00 00


    I tried to find a mathematical formula but could not for the whole string
    I was however able to get some as described below.
    First of all you have your encrypted string as I described in a previous posting
    With PRINCESS that was F1 F6 DB EA CA CF F9 F9

    This string is broken into threes like this

    F1 F6 DB … EA CA CF … F9 F9 00

    Now these three in a group needs to fill 4 bytes and if you multiply the group with 3F you will get close except because of losses in the division the program does ( the bit shifting shr bl 04 for example is divide by h10) it will not be accurate.

    We need

    __ __ __ __ … __ __ __ __ … __ __ __ __ three groups of 4 bytes

    For the first position in each group we take the first byte in each three group, multiply it with 4h, and divide it with 10h

    We put the result in the first position of group of 4 thus: ( F1,F6,DB) F1 x 4 / 10 = 3C

    3C __ __ __ … 3A __ __ __ … 3E __ __ __

    The last position in the four group is just a transfer of the last byte of the three group thus :
    ( F1,F6,DB) ,DB

    3C __ __ DB … 3A __ __ CF … 3E __ __ 00

    The two middle positions I could not find a formula for so I had to estimate and trail and error

    Princess




    Princess


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Princess's Tread (Princess) (29-Jan-99 15:08:40)

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