CrackMe® Practices for Newbies
VBCrackMe 6 by Eternal Bliss

Re: Joseph's Thread---Timer
Saturday, 06-Mar-99 21:19:06

    Greetings everyone,

    The three little windows flashing the green numbers at the top of the target's windows represent a clever timing device using three sets of numbers let us name them as Num1, Num2, and num3.
    Each one of these number is associated with one of three other numbers which are position offset numbers. These numbers are: 120, 1200. And 2280. 120 is for the most left box, 1200 is fore the middle box, and 2280 is for the right most box. These numbers rotate so that each of the displayed numbers will displayed in a different box each time in the order 1, 2, and three.

    Here is the initial position and values of the three numbers:
    First tick
    Num1 Num2 Num3
    Offset Number Offset Number Offset Number
    1200 9947 2280 84 120 19642
    Second tick
    Num1 Num2 Num3
    Offset Number Offset Number Offset Number
    2280 9894 120 167 1200 19287

    Third tick
    Num1 Num2 Num3
    offset Number Offset Number Offset Number
    12 9841 1200 250 2280 18932


    This way and for the first tick 19642 will be displayed in the left little window, 9947 will be displayed in the middle little window and 84 in the right little window.
    For tick two 167 will be displayed in the left little window, 19287 will be displayed in the middle little window, and 9894 will be displayed in the right little window.
    For tick three 9841 will be displayed in the left little window, 250 will be displayed in the middle little window and 18932 will be displayed in the right little window.

    If you take a close look at these numbers you will notice that Num1 is decreased by 53 each tick, Num2 is increased by 83 each tic, an Num3 is decrease by 355 each tick. Num3 is the most significant of the three since it is the time out counter. As long as Num3 is equal or greater than 355 the timer keeps ticking but once it goes below 355 you get the "You ran out of time message". On bases of the above information you may calculate the number of ticks you have before you run out of time, and if you want me to tell you, it takes 55 ticks to time out, and if you look at the numbers in the three little windows this is what you will see:
    Num1 will be displayed in the right little window and equal to 7032 which is 9947 - (55*53), Num2 will be displayed in the left little window and equal to 4649 which is 84 + (55*83), and Num3 will be displayed in the middle little window and equal to 17 which is 19642 - (55*355).

    Having found all this out and said it, I am still not clear to how this may be tide with finding the serial number. Could the serial number be one of the values Num1, Num2, or Num3 acquire? I shall try some of them especially those in Num1 and Num2.

    Best regards,
    Joseph


    Joseph


Message thread:

Joseph's Thread (Joseph) (06-Mar-99 16:55:41)

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