Re: Re:Question Wednesday, 31-Mar-99 14:21:43 Andy is quite right, and the problem you are asking about is a problem in modular arithmetic. You asked about: 79dfh + (5bfh * X) = Y, Y = 7777h and how to find X. In fact you really need to consider 79dfh + (5bfh * X) = 7777h mod (2^32) which is a completely different problem. You no longer consider the division, but the inverse of 5bf mod 2^32 Cronos Cronos |
Joseph's Thread (Question to Cronos) (30-Mar-99 23:45:59) |