Lingo Dictionary > O-R > offset() (string function) |
![]() ![]() ![]() |
offset() (string function)
Syntax
offset(
stringExpression1
,
stringExpression2
)
Description
Function; returns an integer indicating the position of the first character of stringExpression1
in stringExpression2
. This function returns 0 if stringExpression1
is not found in stringExpression2
. Lingo counts spaces as characters in both strings.
On the Macintosh, the string comparison is not sensitive to case or diacritical marks. For example, Lingo considers a and Å to be the same character on the Macintosh.
Example
This statement displays in the Message window the beginning position of the string "media" within the string "Macromedia":
put offset("media","Macromedia")
The result is 6.
Example
This statement displays in the Message window the beginning position of the string "Micro" within the string "Macromedia":
put offset("Micro", "Macromedia")
The result is 0, because "Macromedia" doesn't contain the string "Micro".
Example
This handler finds all instances of the string represented by stringToFind
within the string represented by input
and replaces them with the string represented by stringToInsert
.
on SearchAndReplace input, stringToFind, stringToInsert output = "" findLen = stringToFind.length - 1 repeat while input contains stringToFind currOffset = offset(stringToFind, input) output = output & input.char [1..currOffset] delete the last char of output output = output & stringToInsert delete input.char [1.. (currOffset + findLen)] end repeat set output = output & input return output end
See also
chars()
, length()
, contains
, starts
![]() ![]() ![]() |