January 1996 Programmer's Challenge
Sliding Tiles
Mail solutions to:
progchallenge@mactech.com
Due Date: 10 January 1996
You have all probably seen small versions of the puzzle that is
the basis for this month's Challenge: a 4-by-4 grid of interlocking
tiles, with one empty tile among the 16 cells allowing the puzzle to
be scrambled by sliding adjacent cells into the empty location. This
month the Challenge is to write code that will unscramble a larger
version of the Sliding Tiles puzzle.
The prototype for the code you should write is:
typedef Boolean /*legalMove*/ (*MoveProc)(
/* Callback procedure to move tile at */
long tileToMoveRow, /* these coordinates into the location */
long tileToMoveCol /* of adjacent empty tile */
);
void SolveTiles(
long *tiles, /* pointer to array of tiles where */
long numRows, /* tile (row,col) is at */
long numCols, /* *(tiles + row*numCols + col) */
MoveProc MakeMove /* Callback procedure to move a tile */
);
You will be given a pointer tiles into an array of tile
values, the number of rows and columns in the puzzle
(numRows and numCols, respectively), and the
address of a callback procedure MakeMove used to tell my
test code about the moves you make to solve the puzzle. The
tiles array will be initialized with the values
0..numRows*numCols-1, in an order scrambled by the calling
routine. The value 0 represents the empty tile.
Your code should make a sequence of calls to MakeMove and
return when the puzzle is solved. Each MakeMove call
exchanges the empty tile with the indicated adjacent tile. The puzzle
is solved when you have moved each tile into its proper location:
moving the tile with value i into location tiles[i]
(i.e., row=i/numCols and col=i%numCols).
The callback routine will be something like the code provided
below:
static long gNumRows,gNumCols; /* initialized by test code */
static long gEmptyRow,gEmptyCol; /* initialized by test code */
static long *gTiles; /* initialized by test code */
#define TileValue(tiles,row,col) *(tiles+(row)*gNumCols+(col))
#define OutOfRange(val,num) (((val)<0) || ((val)>=(num)))
static Boolean MakeMove(long tileToMoveRow,long tileToMoveCol)
{
long diff;
if (OutOfRange(tileToMoveRow,gNumRows)) return false;
if (OutOfRange(tileToMoveCol,gNumCols)) return false;
if (tileToMoveRow == gEmptyRow) {
diff = tileToMoveCol - gEmptyCol;
} else if (tileToMoveCol == gEmptyCol) {
diff = tileToMoveRow - gEmptyRow;
} else {
return false;
}
if ((diff != -1) && (diff != 1)) return false;
TileValue(gTiles,gEmptyRow,gEmptyCol) =
TileValue(gTiles,tileToMoveRow,tileToMoveCol);
gEmptyRow = tileToMoveRow;
gEmptyCol = tileToMoveCol;
TileValue(gTiles,gEmptyRow,gEmptyCol) = 0;
return true; //this is an addition - more details
}
As an example, given the initial conditions:
long tiles[] = {1,4,0,3,5,2};
SolveTiles(tiles,2,3,MakeMove);
... you could generate the following moves:
MakeMove(1,2);
MakeMove(1,1);
MakeMove(0,1);
MakeMove(0,0);
... to transform the puzzle like this:
1 4 0 ==> 1 4 2 ==> 1 4 2 ==> 1 0 2 ==> 0 1 2
3 5 2 3 5 0 3 0 5 3 4 5 3 4 5
It turns out that half of the possible permutations of the values
0..numRows*numCols-1 are "illegal" in that they cannot be
reached from the "solved" state. The calling routine will provide a
legal starting state - you don't have to worry about the puzzle being
unsolvable.
The number of moves you make to solve the puzzle is not an
explicit criterion in determining the winner, but the winner will be
determined by total execution time, including the time used by the
callback routine, as we did in the Master MindReader challenge a few
months back. Note that you are not permitted to optimize the callback
routine - its purpose is to provide a fixed time penalty for each
move your solution routine makes.
This will be a native PowerPC Challenge, scored using the Symantec
8.0.3 compiler. Good luck.
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