integer
Section: Perl Programmers Reference Guide (3)
Updated: perl 5.005, patch 02
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NAME
integer - Perl pragma to compute arithmetic in integer instead of double
SYNOPSIS
use integer;
$x = 10/3;
# $x is now 3, not 3.33333333333333333
DESCRIPTION
This tells the compiler to use integer operations
from here to the end of the enclosing BLOCK. On many machines,
this doesn't matter a great deal for most computations, but on those
without floating point hardware, it can make a big difference.
Note that this affects the operations, not the numbers. If you run this
code
use integer;
$x = 1.5;
$y = $x + 1;
$z = -1.5;
you'll be left with $x == 1.5, $y == 2 and $z == -1. The $z
case happens because unary - counts as an operation.
See the section on Pragmatic Modules in the perlmod manpage.
Index
- NAME
-
- SYNOPSIS
-
- DESCRIPTION
-
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