integer

Section: Perl Programmers Reference Guide (3)
Updated: perl 5.005, patch 02
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NAME

integer - Perl pragma to compute arithmetic in integer instead of double  

SYNOPSIS

    use integer;
    $x = 10/3;
    # $x is now 3, not 3.33333333333333333


 

DESCRIPTION

This tells the compiler to use integer operations from here to the end of the enclosing BLOCK. On many machines, this doesn't matter a great deal for most computations, but on those without floating point hardware, it can make a big difference.

Note that this affects the operations, not the numbers. If you run this code

    use integer;
    $x = 1.5;
    $y = $x + 1;
    $z = -1.5;


you'll be left with $x == 1.5, $y == 2 and $z == -1. The $z case happens because unary - counts as an operation.

See the section on Pragmatic Modules in the perlmod manpage.


 

Index

NAME
SYNOPSIS
DESCRIPTION

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Time: 15:39:53 GMT, July 31, 2024